Array notation is a kind of notation for large numbers. Comparing to combinatoric functions, array notation has more complex definition, but easier to evaluate. We’ve known some array notations, such as Bowers’ exploding array function (BEAF), Bird’s array notation (BAN), extensible-E system (ExE), and hyperfactorial array notation (HAN).

Here I bring a **strong** array notation, and it goes far away from the notations mentioned above. It’s made up of several parts shown below.

The following 7 parts make the array notation as strong as R function, and they’re called the **first generation**.

- Linear array notation (LAN)
- Extended array notation (exAN)
- Expanding array notation (EAN)
- Multiple expanding array notation (mEAN)
- Primary dropping array notation (pDAN)
- Secondary dropping array notation (sDAN)
- Dropping array notation (DAN)

On Oct 21, 2017, the rules (for lbrace immediately before a non-1 entry) from exAN to DAN were updated, avoiding the recursion level platform.

The following 5 parts are my first attempt to go beyond R function (i.e. the **second generation**), but they don’t work.

- Nested dropper array notation (NDAN)
- Dropper-expanding notation (DEN)
- Multiple dropper-expanding notation (mDEN)
- Second-order dropper-expanding notation (soDEN)
- Higher-order dropper-expanding notation (hoDEN)

The following 5 parts are my second attempt to second generation, but they still don’t work.

- Nested dropper array notation (NDAN)
- Weak dropper-expanding notation (WDEN)
- Multiple weak dropper-expanding notation (mWDEN)
- Weak dropper-multiexpanding notation (WDmEN)
- Primary dropper-dropping notation (pDDN)

What is the main difference between computable functions and uncomputable functions? Is it that computable functions use finite time and space and uncomputable functions use infinite time and space? Is this the reason?

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A Turing-computable function can be simulated in finite time by a Turing machine. An uncomputable function is a function which is not computable.

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So for instance, the function f(3) = 3^^^^10 is computable, because a Turing machine could take 3 as input on it’s tape and produce the value (output) of 3^^^^10 in finite time? An uncomputable function goes beyond finite time?

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Yes, the first number is computable. As for your second question, even though there exist constructs such as infinite time Turing machines (ITTMs), there still exist functions even those cannot compute, such as, e.g., the ITTM Busy Beaver function.

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I think I’m starting to understand. Turing machines can compute functions, because of their infinite memory tapes and runtime, but Turing machines can not compute themselves. A nth level Turing machine can not go beyond it’s self or simulate it’s self.

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Well, there do exist universal Turing machines which can simulate all other Turing machines, but none can, say, solve the Halting Problem. This is the case with most TM derivatives; for many, you can build a version of the Busy Beaver function which neither it nor less powerful machines can compute.

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Are the states of Turing machines in the same category with hyperoperators like +,-,÷,*, and up arrows?

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Although every hyperoperation can be simulated by some Turing machine, not every function computable by Turing machines can be represented only with hyperoperations.

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So a Turing machine could compute the function f(10) = agoraphobia = E100 &(&(&(…&(&(&({#,#,1,2})))…)))100 w/100 &’s (Sbiis Saibian’s number), because it has an infinitely long tape in both directions (memory storage space) and infinite runtime. It just needs enough states to do so. The states are the Turing machine’s source of computational power. Is this correct?

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A Turing machine must halt in a finite amount of time, but the main power of the Turing machine lies in its arbitrarily long tape.

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How does the Church-Kleene ordinal relate to Turing machines?

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If a Turing machine were to compute the function f(3) = Graham’s number, does that mean that a Turing machine would take 3 consecutive 1s as an input, then operate for a finite number of steps, then halt with a Graham’s number of consecutive 1s left on it’s tape?

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It depends on your I/O encoding scheme; Turing machines by themselves don’t have any notions of this.

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How do Computable functions relate to the Halting problem?

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I would like to ask a few questions about functions and algorithms. So addition is the function and add or adding is the algorithm, multiplication is the function and multiply or multiplying is the algorithm, exponation is the function and exponate or exponating is the algorithm, tetration is the function and tetrate or tetrating is the algorithm. Is this correct?

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What is the limit of SAN with your plans?

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Does anyone know how many symbols it would take to define (pDDN) in the language of First Order Set Theory (FOST)?

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maybe 200.

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Hypcos how many levels of (pDDN) would it take to reach Rayo’s number?

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Uncomputably many levels. All these notations are actually computable.

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Even BIG FOFT, okay how about the limit of pDAN?

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SAN can be extended: +’ is dropper-droppers for ::::…+ and ++ is dropper-droppers for +::::…, then we can defined nested droppers for +++…., like (N^+)

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Hypcos what are the circles (o) used for in your Strong Array Notation?

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The circle is a dropper in NDAN. Read the NDAN page for more details.

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Hypcos which part of your Strong Array Notation has recursion level psi(OMEGA omega)?

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The limit growth rate of mEAN is ψ(Ω_ω).

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So that is comparable to legion array space?

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BEAF is not well-defined beyond tetrational arrays, and so is legion array space.

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Okay.

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Hypcos which part of your Strong Array Notation has the Large Veblen Ordinal (LVO)?

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Separator {1{1`1`2`}2} has recursion level LVO, and first appears in expanding array notation (EAN).

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Hypcos how would you describe TREE(3) with your Strong Array Notation?

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The value of TREE(3) is too hard to work out. It has a lower bound of s(3, s(3, 262138 {1 {1`1,2 `} 2} 2) {1 {1`1,2 `} 2} 2 {1 {1`1,2 `} 5} 2). However, its upper bounds are much weaker, because we don’t know the growth rate of TREE(n). We just know TREE(3)<SSCG(3), where SSCG(n) grows slower than s(n,n{1,,2,2}2).

So s(3, s(3, 262138 {1 {1`1,2 `} 2} 2) {1 {1`1,2 `} 2} 2 {1 {1`1,2 `} 5} 2) < TREE(3) << s(3,3 {1,,2,2} 2).

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Cool.

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Hypcos how would you describe a Golapulus (10^100 & 10 & 10) with your Strong Array Notation?

Where would a Golapulus be in your Strong Array Notation?

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Impossible

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Hypcos how would you describe a 10^100 array of 10s array of 10s with your Strong Array Notation?

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That would be approximately s(10,s(10,s(10,100){2}2){2}2) in exAN.

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You are wrong. & isn’t defined.

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Hyp cos how would you express Meameamealokkapoowa Oompa with your Strong Array Notation?

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Meameamealokkapoowa Oompa is not well-defined. What’s more, Bowers’ googolisms beyond triakulus are not well-defined.

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Okay.

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So we express BEAF up to {1,,2} separator?

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Indeed. {1,,2} is the same level as tettrational BEAF arrays.

However BEAF and SAN are not equivalent at that point.

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Why you ran out of ideas about extensions?

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Aarex I am a huge fan of your work with large numbers. I have been studying your work with large numbers for years. Could you show me the steps to go from Otoperoogol to Otopersuperoogol? These numbers are listed on your Extensible Up-arrow System part 4 Dimensional/Nested Array Up-arrow webpage.

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My old googology site is closed, silly you.

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The question was asked before you closed it, silly. And I’m sure he’ll find the time to bring back the extended arrow notation some time in the future…

And he’s made primary dropper-dropping notation, part 12. Whether he plans to make a part 13, I don’t know.

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I have the idea on pDDN notation, going beyond than +.

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What’s the definition of the iterator in exAN?

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Iterator is defined as the 2nd entry (not in separators) in the array.

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Cant you like, fix it?

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It seems like he already has. (or at least tried to) The new NDAN is a replacement for the old one, and WDEN and mWDEN are analogues to DEN and mDEN. WDmEN seems to go a different direction from soDEN and hoDEN; perhaps he sees this as a better/stronger way to extend things.

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Can you make the new version of DEN? (sDEN)

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Can you explain in more detail why the latter five parts don’t work?

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In NDAN, there is the problem cause infinite loop.

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Still occurs in his second attempt. I have second thoughts.

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